3-2(x^2+1)=9x=4

Solution for 3-2(x^2+1)=9x=4 equation:

3-2(x^2+1)=9x=4

We move all terms to the left:

3-2(x^2+1)-(9x)=0

We add all the numbers together, and all the variables

-9x-2(x^2+1)+3=0

We multiply parentheses

-2x^2-9x-2+3=0

We add all the numbers together, and all the variables

-2x^2-9x+1=0

a = -2; b = -9; c = +1;
Δ = b2-4ac
Δ = -92-4·(-2)·1
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{89}}{2*-2}=\frac{9-\sqrt{89}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{89}}{2*-2}=\frac{9+\sqrt{89}}{-4}
$